[BOJ] 5397번 : 키로거

1. problem : 

https://www.acmicpc.net/problem/5397

 

 

2. solution 1 : 

#include <bits/stdc++.h>

using namespace std;

int main(void) {
    ios::sync_with_stdio(0);
    cin.tie(0);

    int testCase;
    cin >> testCase;

    while (testCase--) {
        list<char> L = {};
        auto cursor = L.begin();
        string init;
        cin >> init;

        for (auto c : init) {
            if (c == '<') {
                if (cursor != L.begin()) cursor--;
            }
            else if (c == '>') {
                if (cursor != L.end()) cursor++;
            }
            else if (c == '-') {
                if (cursor != L.begin()) {
                    cursor--;
                    cursor = L.erase(cursor);
                }
            }
            else {
                L.insert(cursor, c);
            }
        }

        for (auto c : L) cout << c;
        
        cout << '\n'; 
    }

    return 0;
}

## barkingdog님의 source code를 보고 따라 했다. 

<출처> https://github.com/encrypted-def/basic-algo-lecture/blob/master/0x04/solutions/5397.cpp